Consider the following data for the given reaction $2 HI_{(g)} \rightarrow H_{2_{(g)}} + I_{2_{(g)}}$. The order of the reaction is:
Experiment $1$ $2$ $3$
$[HI] \ (mol \ L^{-1})$ $0.005$ $0.01$ $0.02$
Rate $(mol \ L^{-1} \ s^{-1})$ $7.5 \times 10^{-4}$ $3.0 \times 10^{-3}$ $1.2 \times 10^{-2}$

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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Similar Questions

For the reaction $A + B \xrightarrow{K} C$,identify the incorrect order of reaction indicated against the rate expression.

The following data is given for the reaction between $A$ and $B$:
$S.NO.$$[A] \ mol \ L^{-1}$$[B] \ mol \ L^{-1}$$Rate \ mol \ L^{-1} \ sec^{-1}$
$I$$1 \times 10^{-2}$$2 \times 10^{-2}$$2 \times 10^{-4}$
$II$$2 \times 10^{-2}$$2 \times 10^{-2}$$4 \times 10^{-4}$
$III$$2 \times 10^{-2}$$4 \times 10^{-2}$$8 \times 10^{-4}$

Which of the following are correct statements?
$(a)$ Rate constant of the reaction is $1 \ mol^{-1} \ L \ sec^{-1}$.
$(b)$ Rate law of the reaction is $k[A][B]$.
$(c)$ Rate of reaction increases four times on doubling the concentration of both the reactants.

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The rate constant for the reaction, $2 \,N_2O_{5(g)} \rightarrow 2 \,N_2O_{4(g)} + O_{2(g)}$ is $4.98 \times 10^{-4} \,s^{-1}$. What is the order of the reaction?

For a second-order reaction,the rate constant is $8 \times 10^{-5} \, M^{-1} \, \text{min}^{-1}$. In how much time will a $1 \, M$ solution decrease to $0.5 \, M$?

........ of a reaction cannot be determined experimentally.

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